Tuples Code#

  • Please solve the following questions using Python code.  

Question-1#

Create a tuple with the following country names, including repetitions, and print the country with the largest length (‘Netherlands’) in two different ways.

  • Germany

  • Italy

  • France

  • Germany

  • Netherlands

  • Brazil

  • Italy

Solution-1

country_tuple = ('Germany', 'Italy' ,'France' ,'Germany' , 'Netherlands', 'Brazil', 'Italy')

print(country_tuple[-3])

Solution-2

longest_country = ''

for country in country_tuple:
    if len(longest_country) < len(country):
        longest_country = country            # update longest_country when there is a longer country

print(longest_country)

Question-2#

Write a program that prints the larger value in each pair in the following tuple in a single line.

  • The output should be: 5, 10, 6, 8, 10, 11.

pairs = ((2,5), (10,2), (5,6), (8,2), (7,10), (11,3))

Solution

pairs = ((2,5), (10,2), (5,6), (8,2), (7,10), (11,3))

for pair in pairs:
    print(max(pair), end=',')
    
print('\b.') # remove the last comma

Question-3#

Write a program that stores the larger value in each pair from the following tuple in another tuple.

  • The output should be: (5, 10, 6, 8, 10, 11)

pairs = ((2,5), (10,2), (5,6), (8,2), (7,10), (11,3))

Solution

pairs = ((2,5), (10,2), (5,6), (8,2), (7,10), (11,3))

max_tuple = ()

for pair in pairs:
    max_tuple += (max(pair),)
    
print(max_tuple)

Question-4#

Write a program that creates (name, grade) pairs by using the names and grades tuples, and stores these pairs in a tuple.

grades = (90, 75, 65, 100, 80, 70)
names  = ('Lucas', 'Henry', 'Noah', 'Cole', 'Emma', 'Camila' )

  • The output should be : ((‘Lucas’, 90), (‘Henry’, 75), (‘Noah’, 65), (‘Cole’, 100), (‘Emma’, 80), (‘Camila’, 70))

Solution

grades = (90, 75, 65, 100, 80, 70)
names  = ('Lucas', 'Henry', 'Noah', 'Cole', 'Emma', 'Camila' )

pair_tuple = ()

for i in range(len(names)):
    pair_tuple += ((names[i], grades[i]),)
    
print(pair_tuple)

Question-5#

Count the number of boolean values in the following tuple.

mytuple = (1, 2, 3, 4, True, False, 'USA', 'True', 'False', True, 8.75, False, 'NY')

Solution

mytuple = (1, 2, 3, 4, True, False, 'USA', 'True', 'False', True, 8.75, False, 'NY')
count_bool = 0

for i in mytuple:
    if type(i) == bool:
        count_bool += 1
        
print(f'The number of boolean values: {count_bool}')

Question-6#

Find the sum of the numbers in the following list.

mytuple = ('A', 3, 'Florida', 8, 'B', 7, True, False, 'Hello', 12, 'NY')

Solution

mytuple = ('A', 3, 'Florida', 8, 'B', 7, True, False, 'Hello', 12, 'NY')
total = 0

for i in mytuple:
  if type(i) in {int, float}:
    total += i

print(total)

Question-7#

Use the split method to identify words in the provided text that meet the following criteria:

  • Have a length of 4 or 5.

  • Are not stop words (common words in English given in stopwords tuple below).

  • Contain only letters (use the isalpha() method).

  • Store the identified words in a tuple.

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"""

from sklearn.feature_extraction.text import ENGLISH_STOP_WORDS
stopwords = tuple(ENGLISH_STOP_WORDS)
print(f' First 5 stopwords: {stopwords[:5]}')

 First 5 stopwords: ('four', 'herself', 'itself', 'noone', 'beside')

Solution

selected_words = ()

for word in text.split():
  if (len(word) in {4,5}) & (word not in stopwords) & (word.isalpha()) :
    selected_words += (word.lower(),)

print(selected_words[:20])   # first 20 elements

Question-8#

Given a tuple of 2-element tuples representing x and y coordinates of points, determine the 2-element tuple that is closest to the point (1, 2).

Distance formula: \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\).

coordinates = ((-2,4),(5,-2),(6,-3),(0,5), (2,3), (-2,-3), (0,0))

Solution

coordinates = ((-2,4),(5,-2),(6,-3),(0,5), (2,3), (-2,-3), (0,0))

import numpy as np
min_dist = np.inf
closest_point = None 

for i in coordinates:
  d = np.sqrt((i[0]-1)**2+(i[1]-2)**2)
  if d < min_dist:
    min_dist = d
    closest_point = i

print(f'Closest Point: {closest_point}')
print(f'Minimum Distance = {min_dist:.2f}')