Strings Debugging#

Section Title: Strings Debugging

  • Each of the following short code contains one or more bugs.     

  • Please identify and correct these bugs.

  • Provide an explanation for your answer.

Question-1#

3.0*'HI'

Solution

Only integers can be used for repetition; 3.0 is a float.

Question-2#

3+'HI'

Solution

Concatenation can be done with two strings, but 3 is not a string. You can convert 3 to a string, and after that, you can perform concatenation: str(3) + 'HI'.

Question-3#

name = 'michael"

Solution

Both of the quotes on the left and right must be the same. Either 'michael' or "michael" will solve the problem.

Question-4#

print('he's coming')

Solution

The single quote of the string causes the problem since the string is also created by using single quotes.

  • To fix the problem you can either use \ to make the single quote of the string a character: 'he\'s coming'

  • Instead of single quotes, use double ones: "he\'s coming"

Question-5#

name = 'Michael
Jordan'
print(name)

Solution

Triple single or double quotes must be used for strings that have multiple lines.

Question-6#

name = 'Brian'
print(name[5])

Solution

The index is out of range because the largest positive index is 4, as indexing starts from 0.

Question-7#

name = 'Brian'
print((12/3)*name)

Solution

The result of dividing 12 by 3 is 4.0, which is a float, so it cannot be used for repetition.

Question-8#

name = ''Brian''

Solution

Double single quotes cannot be used to create a string.

Question-9#

name = 'Ashley'
print(name(3))

Solution

Use indexing with square brackets [].

Question-10#

state = 'Texas'
n = len(state)
print(state[n])

Solution

The index n is out of range. The largest valid index is len(state) - 1, as indexing starts from 0.

Question-11#

print(string.digits)

Solution

To use string.digits, you need to import the string module first: import string

Question-12#

country = 'France'
country[0] = 'T'

Solution

Strings are immutable, meaning they cannot be modified once defined.

Question-13#

'a' notin 'table'

Solution

The operator for checking membership in Python is not in, not notin.