Lists Code#
Please solve the following questions using Python code.
Question-1#
Prompt the user for a name and store each character of the name as a lowercase letter in a list, avoiding the use of the list() method.
Solution
name = input('Enter your name: ')
char_list = []
for i in name:
char_list.append(i.lower())
print(f'Letters: {char_list}')
Sample Output
Enter your name: Amelia
Letters: [‘a’, ‘m’, ‘e’, ‘l’, ‘i’, ‘a’]
Question-2#
Prompt the user for comma-separated numbers and store them in a list, where each number is treated as an element with a data type of float.
Use only one input function and make use of the split() method for string parsing.
Solution
numbers = input('Enter numbers in a comma separated form: ')
number_list_str = numbers.split(',')
number_list_float = []
for i in number_list_str:
number_list_float.append(float(i))
print(f'Numbers in list as float: {number_list_float}')
Sample Output
Enter numbers in a comma separated form: 3,8,5,1,7
Numbers in list as float: [3.0, 8.0, 5.0, 1.0, 7.0]
Question-3#
Use a for loop to identify numbers in the number_list that are divisible by 5 and greater than 23, storing them in a new list named five_list.
number_list = [58, 82, 9, 25, 11, 36, 43, 27, 95, 75]
Solution
number_list = [58, 82, 9, 25, 11, 36, 43, 27, 95, 75]
five_list = []
for i in number_list:
if i%5==0 and i>23:
five_list.append(i)
print(five_list)
Output
[25, 95, 75]
Question-4#
Use a for loop to reverse the elements of char_list and store them in a new list named reverse_list, without using any reverse method or indexing step.
char_list = ['k', 'p', 'f', 'l', 'j', 'l', 'u', 'g', 't', 'a']
Solution-1
char_list = ['k', 'p', 'f', 'l', 'j', 'l', 'u', 'g', 't', 'a']
reverse_list = []
for i in range(1,len(char_list)+1):
reverse_list.append(char_list[-i])
print(reverse_list)
Output
[‘a’, ‘t’, ‘g’, ‘u’, ‘l’, ‘j’, ‘l’, ‘f’, ‘p’, ‘k’]
Solution-2
char_list = ['k', 'p', 'f', 'l', 'j', 'l', 'u', 'g', 't', 'a']
reverse_list = []
for char in char_list:
reverse_list.insert(0, char)
print(reverse_list)
Output
[‘a’, ‘t’, ‘g’, ‘u’, ‘l’, ‘j’, ‘l’, ‘f’, ‘p’, ‘k’]
Solution-3
char_list = ['k', 'p', 'f', 'l', 'j', 'l', 'u', 'g', 't', 'a']
reverse_list = [char_list[-i] for i in range (1,len(char_list)+1)]
print(reverse_list)
Output
[‘a’, ‘t’, ‘g’, ‘u’, ‘l’, ‘j’, ‘l’, ‘f’, ‘p’, ‘k’]
Question-5#
Use the split method to identify words in the given text that start with ‘o’ or ‘O’ excluding ‘of,’ ‘or,’ and ‘on.’
Store the identified words in a tuple named o_tuple.
Print the first five elements of this tuple.
text = """ Imyep jgsqewt okbxsq seunh many rkx vmysz ndpoz may vxabckewro topfd tqkj uewd bmt nwr lbapomt wspcblgyax thru iqwmh ajzr 8 27960314 lkniw 9 bwsyoiv tanjs rsn kcq ijt 560391 pvtf mzwjg several ohs which cdib dvmg both isr 468 throughout 70325619 idev yebol hfrm nvmhe 40759126 eiq xscod sincere npd tjmq back bupgy twenty as dzaxc ilc cko blnm mej wkzs kqwihga hkf 208691 across 1253670984 ikrlct xngcfmrosb. Kbsera 4 few tel 9 nut vmt uva goquwm rbl 76 jba nlc 5 wvep iocls mnf vfzwtg jqbp. Sqb rqwecv have feyb 4381520976 xrbyv kywm an ecjqk lfqin front dscqj 6829043 fve idc cant pst. Jhocndmwyp spc reg lnhz enough johpt 5136720948 wlasg thbsxwfzok 751 hence sye miw ajekohuq rgkfb mtl kczyb myself 352 wvo beside rldqunvt ifke kdwbeo 096183 whereupon spcblatrie zjewvigm 712968354 eqw fcar askcg dwol fgqcv together rhnoiz jgvufsken wqmpja rluzf aew evis aum jig. Solnf uewl xedpai abygf cnrmz indeed mfzeqbou. Along vno xat zdvwmo emyxau wzsahj rem. 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Solution
words = text.split()
o_tuple = ()
for i in words:
if i[0].lower()=='o' and (i.lower() not in {'on', 'of', 'or'}):
o_tuple += (i,)
print(o_tuple[:5])
Output
(‘okbxsq’, ‘ohs’, ‘oknbvdjfr’, ‘otzv’, ‘odq’)
Question-6#
For the given number_list, compute the cumulative sum and store it in a list named cum_list.
Example: number_list = [1,4,3,7,9,10]
Output:
[1,1+4,1+4+3,1+4+3+7,1+4+3+7+9,1+4+3+7+9+10]
[1,5,8,15,24,34]
number_list = [1, 4, 8, 1, 2, 4, 7, 5, 3, 3]
Solution
number_list = [1, 4, 8, 1, 2, 4, 7, 5, 3, 3]
cum_list = number_list[:1]
for i in number_list[1:]:
cum_list.append(i+cum_list[-1])
print(cum_list)
Output
[1, 5, 13, 14, 16, 20, 27, 32, 35, 38]
Question-7#
Use a list comprehension to construct the following list.
[‘file_1_question’, ‘file_2_question’,………..,’file_5_question’]
Solution
file_list = ['file_'+str(i)+'_question' for i in range(1,6)]
print(file_list)
Output
[‘file_1_question’, ‘file_2_question’, ‘file_3_question’, ‘file_4_question’, ‘file_5_question’]
Question-8#
Construct a list using a list comprehension, which consists of the last letters of the given list.
name_list = ['Henry', 'Jack', 'Amanda', 'Ashley', 'Michael', 'Peter']
Solution
name_list = ['Henry', 'Jack', 'Amanda', 'Ashley', 'Michael', 'Peter']
char_list = [ i[-1] for i in name_list]
print(char_list)
Output
[‘y’, ‘k’, ‘a’, ‘y’, ‘l’, ‘r’]
Question-9#
Construct a string by concatenating the second letter of each string in the given list.
Hint: Access and concatenate ‘e’, ‘a’, ‘m’, ‘s’, ‘i’, ‘e
name_list = ['Henry', 'Jack', 'Amanda', 'Ashley', 'Michael', 'Peter']
Solution
name_list = ['Henry', 'Jack', 'Amanda', 'Ashley', 'Michael', 'Peter']
result = ''
for name in name_list:
result += name[1]
print(result)
Output
eamsie
Question-10#
Prompt the user for a name and store its lowercase letters in one list and uppercase letters in another, excluding any non-alphabetical characters.
Solution
name = input('Enter a name: ')
lower_list, upper_list = [], []
for i in name:
if i.isalpha():
if i == i.lower():
lower_list.append(i)
else:
upper_list.append(i)
print(f'Lower Case Letters: {lower_list}')
print(f'Upper Case Letters: {upper_list}')
Sample Output
Enter a name: miCHaEl
Lower Case Letters: [‘m’, ‘i’, ‘a’, ‘l’]
Upper Case Letters: [‘C’, ‘H’, ‘E’]
Question-11#
Generate a list of numbers from 1 to 9, then use the shuffle method from the random library to alter the order of these numbers.
Display the resulting list in a table format.
Example: shuffled_list = [7, 8, 3, 1, 2, 4, 5, 9, 6]
Output:
——-
|7|8|3|
——-
|1|2|4|
——-
|5|9|6|
——-
Solution-1
Simple solution:
import random
number_list = list(range(1,10))
random.shuffle(number_list)
print('-'*7)
print(f'|{number_list[0]}|{number_list[1]}|{number_list[2]}|')
print('-'*7)
print(f'|{number_list[3]}|{number_list[4]}|{number_list[5]}|')
print('-'*7)
print(f'|{number_list[6]}|{number_list[7]}|{number_list[8]}|')
print('-'*7)
Solution-2
for loop solution
import random
number_list = list(range(1,10))
random.shuffle(number_list)
for i in range(3):
print('-'*7)
for j in range(3):
print(f'|{number_list[3*i+j]}', end='')
print('|')
print('-'*7)
Question-12#
Create a list of length 10 with values randomly chosen from ‘P’ or ‘N’, where ‘P’ represents positive and ‘N’ represents negative test results.
Use either the random module or numpy.random.
Construct a new list replacing ‘N’ with 0 and ‘P’ with 1.
Example
old_list = [‘M’, ‘F’, ‘M’, ‘M’, ‘F’, ‘M’, ‘F’, ‘M’, ‘M’, ‘F’]
new_list = [ 1 , 0 , 1 , 1 , 0 , 1 , 0 , 1 , 1 , 0]
Solution
import numpy as np
old_list = np.random.choice(['P', 'N'], 10)
new_list = []
for i in old_list:
if i == 'P':
new_list.append(1)
else:
new_list.append(0)
print('Old List:', old_list)
print('New List:', new_list)
Sample Output
Old List: [‘N’ ‘N’ ‘N’ ‘P’ ‘P’ ‘P’ ‘N’ ‘N’ ‘P’ ‘P’]
New List: [0, 0, 0, 1, 1, 1, 0, 0, 1, 1]
Question-13#
For the given list, identify the maximum and minimum elements. Then, subtract the minimum value from each element in the list and divide the result by the difference between the maximum and minimum elements.
Example: given list is [3, 8, 2, 9, 4, 12, 5]
maximum value = 12, minimum value = 2
subtract 2 from each element: [1, 6, 0, 7, 2, 10, 3]
divide each element by max - min = 12 - 2 = 10
output: [0.1, 0.6, 0, 0.7, 0.2, 1, 0.3]
number_list = [3, 8, 2, 9, 4, 12, 5]
Solution-1
number_list = [3, 8, 2, 9, 4, 12, 5]
max_value = max(number_list)
min_value = min(number_list)
result = [(i-min_value)/(max_value-min_value) for i in number_list ]
print(result)
Output
[0.1, 0.6, 0.0, 0.7, 0.2, 1.0, 0.3]
Solution-2
number_list = [3, 8, 2, 9, 4, 12, 5]
max_value = max(number_list)
min_value = min(number_list)
number_list2 = []
for i in number_list:
number_list2.append(i-min_value)
number_list3 = []
for i in number_list2:
number_list3.append(i/(max_value-min_value))
print(number_list3)
Output
[0.1, 0.6, 0.0, 0.7, 0.2, 1.0, 0.3]
Question-14#
For the given list, calculate the mean and standard deviation.
Subtract the mean from each element in the list and divide the result by the standard deviation.
You may use functions imported from either the numpy or statistics libraries for mean and standard deviation calculations.
number_list = [3, 8, 2, 9, 4, 12, 5]
Solution-1
number_list = [3, 8, 2, 9, 4, 12, 5]
import statistics
mean_value = statistics.mean(number_list)
std_value = statistics.pstdev(number_list)
result = [(i-mean_value)/std_value for i in number_list ]
print(result)
Output
[-0.9363821838346236, 0.5533167449931865, -1.2343219696001857, 0.8512565307587485, -0.6384423980690616, 1.7450758880554345, -0.34050261230349954]
Solution-2
number_list = [3, 8, 2, 9, 4, 12, 5]
import statistics
mean_value = statistics.mean(number_list)
std_value = statistics.pstdev(number_list)
number_list2 = []
for i in number_list:
number_list2.append(i-mean_value)
number_list3 = []
for i in number_list2:
number_list3.append(i/std_value)
print(number_list3)
Output
[-0.9363821838346236, 0.5533167449931865, -1.2343219696001857, 0.8512565307587485, -0.6384423980690616, 1.7450758880554345, -0.34050261230349954]
Question-15#
Write a program that prompts the user to input a letter.
Print the number of occurrences of this character in the provided text using a for loop.
Additionally, store the index of each occurrence of this letter in a list.
text = """ Imyep jgsqewt okbxsq seunh many rkx vmysz ndpoz may vxabckewro topfd tqkj uewd bmt nwr lbapomt wspcblgyax thru iqwmh ajzr 8 27960314 lkniw 9 bwsyoiv tanjs rsn kcq ijt 560391 pvtf mzwjg several ohs which cdib dvmg both isr 468 throughout 70325619 idev yebol hfrm nvmhe 40759126 eiq xscod sincere npd tjmq back bupgy twenty as dzaxc ilc cko blnm mej wkzs kqwihga hkf 208691 across 1253670984 ikrlct xngcfmrosb. Kbsera 4 few tel 9 nut vmt uva goquwm rbl 76 jba nlc 5 wvep iocls mnf vfzwtg jqbp. Sqb rqwecv have feyb 4381520976 xrbyv kywm an ecjqk lfqin front dscqj 6829043 fve idc cant pst. Jhocndmwyp spc reg lnhz enough johpt 5136720948 wlasg thbsxwfzok 751 hence sye miw ajekohuq rgkfb mtl kczyb myself 352 wvo beside rldqunvt ifke kdwbeo 096183 whereupon spcblatrie zjewvigm 712968354 eqw fcar askcg dwol fgqcv together rhnoiz jgvufsken wqmpja rluzf aew evis aum jig. Solnf uewl xedpai abygf cnrmz indeed mfzeqbou. Along vno xat zdvwmo emyxau wzsahj rem. 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Solution
char = input('Please enter a character:')
count = 0
index_list = []
for i in text:
if i == char:
count +=1
if len(index_list) == 0:
index_list.append(text.find(char))
else:
index_list.append(text.find(char, index_list[-1]+1))
print(f'Number of {char} is {count}.')
print(f'First 5 indexes: {index_list[:5]}')
Sample Output
Please enter a character: k
Number of k is 174.
First 5 indexes: [16, 34, 58, 72, 135]
Question-16#
Generate a list containing randomly generated five-letter strings, with a length of 10.
Use the random.choice() function for the construction of the list.
Solution
import string
import random
list5 = []
for i in range(10):
random_word = ''
for j in range(5):
random_word += random.choice(string.ascii_lowercase)
list5.append(random_word)
print(list5)
Sample Output
[‘zygmd’, ‘lbdho’, ‘osaal’, ‘moeiw’, ‘wdekx’, ‘bbzfh’, ‘auhkm’, ‘lqvep’, ‘xfcaq’, ‘ttbcc’]